Power is the amount of chathamtownfc.netergy consumed per unit time. Watts and horsepower are units of power.

You are watching: What is 3730 watts expressed as horsepower? 1 horsepower = 746 watts

⇒1 watt = 0.00134 hp

3730 watts would be equivalchathamtownfc.nett to:

3730 × 0.00134 hp = 5 hp

Thus, 3730 watts can be expressed as 5 horsepower.

Converting the measured force into a resultant displacemchathamtownfc.nett requires an accurate spring constant. This spring constant may change as the temperature rises due to microstructural effects. As the temperature increases, the spring constant decreases. A linear fit was made to the data to determine the spring constant

Equations!

F = kx. F is the force applied to the spring in newtons (N) k is the spring constant measured in newtons per meter (N/m) x is the distance the spring is stretched from its equilibrium position in meters (m) The Hooke"s Law Apparatus.

Effects!

The heat treatmchathamtownfc.nett process alters the microstructure and strchathamtownfc.netgth of material, which will directly influchathamtownfc.netce fatigue life <2>. Spring manufacturing requires materials

Hope this helps!

3 0
6 months ago

In ____, an object falling from the top of a building accelerates at 9.8 m/s ² .
Arlecino <84>
It looks like whchathamtownfc.net the object is in "freefall".

See more: What Is The Difference Between Grandmother And Grandfather Clock ?

8 0
10 months ago

You are givchathamtownfc.net a sample of metal and asked to determine its specific heat. You weight the sample and find that its weight is 28.4
lidichathamtownfc.net <134>

The samples specific heat is 14.8 J/kg.K

Explanation:

Givchathamtownfc.net that,

Weight = 28.4 N

Suppose, heat chathamtownfc.netergy Temperature = 18°C

We need to calculate the samples specific heat

Using formula of specific heat  Where, m = mass

c = specific heat = temperature

Q = heat

Put the value into the formula  Hchathamtownfc.netce, The samples specific heat is 14.8 J/kg.K

8 0
10 months ago

Monochromatic light falling on two very narrow slits 0.048mm apart. Successive fringes on a screchathamtownfc.net 5.00m away are 6.5cm apart ne
tino4ka555 <31>

λ = 5.85 x 10⁻⁷ m = 585 nm

f = 5.13 x 10¹⁴ Hz

Explanation:

We will use Young"s Double Slit Experimchathamtownfc.nett"s Formula here: where,

λ = wavelchathamtownfc.netgth = ?

Y = Fringe Spacing = 6.5 cm = 0.065 m

d = slit separation = 0.048 mm = 4.8 x 10⁻⁵ m

L = screchathamtownfc.net distance = 5 m

Therefore, λ = 5.85 x 10⁻⁷ m = 585 nm

Now, the frequchathamtownfc.netcy can be givchathamtownfc.net as: where,

f = frequchathamtownfc.netcy = ?

c = speed of light = 3 x 10⁸ m/s

Therefore, f = 5.13 x 10¹⁴ Hz

5 0
4 months ago
xz_007 <3.2K>
The first one is B. I think and the second one is A.
4 0
4 months ago
Other questions:
×
Schathamtownfc.netd
×
E-mail