You are watching: How to find the height of a flagpole using its shadow
I"m confused about the provided problem over because ns can"t determine yet the length of the shadow, and likewise I"m grounding at the angle of depression, in i beg your pardon I claimed that it has to be the angle of elevation instead.
My solution:
$sinleft(58^circ ight)=fracxx-3$
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edited january 22 "18 at 22:08
Xtravagant
asked january 22 "18 at 21:42
XtravagantXtravagant
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First, we draw a flagpole, $x$m long. Climate we attract a shadow that is $x-3$m long. Climate the sunlight ray i m sorry casts the shadow connects the optimal of the pole and TOP of the shadow. This means the angle created by the hypotenuse (the sunlight ray) and the zero is $58^o$. Currently we have $ an 58^o=fracxx-3$, offering us $x an 58^o-3 an 58^o=x$. We lug $x$ to one side, having $xleft( an 58^o-1 ight)=3 an 58^o$. $x=7.997...=8.00left(3sf ight)$.
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edited Feb 19 "20 in ~ 8:48
wuyudi
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answered january 22 "18 at 21:52
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