We’re asked to calculate the standardenthalpy of development (ΔH°f)for naphthalene (C10H8) based on the standardenthalpy of burning (ΔH°rxn)and the chemical equation.

You are watching: Calculate the standard enthalpy of formation of naphthalene

Recall thatΔH°rxncan it is in calculated indigenous the reactants and products involved:

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We’re given theΔH°rxnfor the burning of 1 mole that C10H8. The chemical equation for the reaction is:

C10H8(s) + 12 O2(g)→10CO2(g) + 4 H2O(l)

First, we make certain the equation is well balanced by checking the the variety of elements on both sides is equal.

Balance C:we have 10 C ~ above the reactant side and 10 C top top the assets side.

Balance H:we have actually 8 H on the reactant side and also 4(2) = 8 H on the commodities side.

Balance O:we have actually 12(2) = 24 O on the reactant side and 10(2) + 4(1) = 24 O on the assets side.


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Problem Details

The standard enthalpy of burning of naphthalene is -5157 kJ/mol. Calculate its standard enthalpy the formation.

The reaction because that the burning of naphthalene is:

C10H8 (s) + 12 O2 (g) → 10CO2 (g) + 4 H2O (l)


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